Question

F(x)= x^2 -16x+63 find the x-intercepts of this function

Answer 1

(7, 0) and (9, 0)

Explanation:

The x-intercepts refers to the points where the graph of the function crosses the x-axis, or simply the zeroes of the function. In this case, we can determine these points analytically or graphically. We simply graph the function;

y = x^2 -16x +63 then determine where the function crosses the x-axis; see the attachment below;

The x-intercepts of this function are;

(7, 0) and (9, 0)

Answer 2

The x-intercepts will be, x= 7 or x =9

Explanation:

f(x)= x^2 -16x+63

At the x-intercept, f(x) is zero.

Therefore;

x² - 16x + 63 = 0

solving it quadratically;

product = 63

Sum = -16

x² - 9x - 7x + 63 = 0

x(x-9) - 7( x-9) = 0

(x-7) (x-9) = 0

x = 7 or x = 9

Therefore;

The x-intercepts will be, x= 7 or x =9