Question

Find the value of k such that the system of equations does not have a solution:

10x+4y=-3
-15x+ky=14

Answer 1

k = -6.

Explanation:

We need to make the left side of the second equation a multiple of the left side of the first one.

We can do this by making k = -6 ( because -15/10 = -6/4).

The second equation becomes

-15x - 6y = 14

Now multiply this by -2/3. We get

10x + 4y = -28/3

but the first equation is 10x + 4y = -3 .

So there are no solutions.

So the answer is k = -6.

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