Answer:
both energy will remain constant and potential energy must be more than the kinetic energy of the block
So correct Graph will be
A) option
Step-by-step explanation:
As we know that kinetic energy of the block is given as
![K = (1)/(2)mv^2](https://img.qammunity.org/2020/formulas/physics/high-school/ivaq26hojo6gz8um6mye6ma7du9v52w8ak.png)
potential energy is given as
![U = mgh](https://img.qammunity.org/2020/formulas/physics/middle-school/8dn7weh0u3z0x50mdn9c63otp1p54f4u28.png)
so when a block is stationary at the surface of table so due to height of the table the potential energy of the block is given as
![U = mgh](https://img.qammunity.org/2020/formulas/physics/middle-school/8dn7weh0u3z0x50mdn9c63otp1p54f4u28.png)
but as we know that the speed of the block is zero
so kinetic energy must be
![K = 0](https://img.qammunity.org/2020/formulas/physics/high-school/r6bcb1d3mszs9nf9jojfzwnawirzmlwvqk.png)
so here in the graph both energy will remain constant and potential energy must be more than the kinetic energy of the block