The terms of an arithmetic sequence are generated by adding a fixed term
every time.
So, we start with
, and we continue with
,
and so on.
As you can see, the general rule is
![a_n = 15+(n-1)r](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nzndz1270xu5ob1mg096diol0qn92dujp0.png)
With this information, we can derive
, knowing that
![a_(100) = 307 = 15+99r \iff 99r = 292 \iff r = (292)/(99)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dqm6ikinfkcvew85l049drhmrzulikct1s.png)
So, the sum of the first 100 terms is
![[tex]\displaystyle \sum_(i=0)^(99) 15+i(292)/(99) = \displaystyle \sum_(i=0)^(99) 15 + \displaystyle (292)/(99)\sum_(i=0)^(99) i = (15\cdot 99) + (292)/(99)(99\cdot 100)/(2) = 1485 + (490342)/(99)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/97gmuz0k5rddfre4l5m0s2m2jq8yqw370k.png)