ANSWER
![y \leqslant - 2x - 2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7uszwrxfs0ov8cg8m0qs6zury33elvdwh2.png)
Step-by-step explanation
The boundary line passes through (-2,2) and (0,-2).
The slope of this line is
![m = ( - 2 - 2)/(0 - - 2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/o4nqdefugm3e1qev0jjrmst4ui9ql0y1di.png)
![m = ( - 4)/(2) = - 2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5wtwb70ktdonvtujwppflxcsqhlwriobb2.png)
The y-intercept is , c=-2.
The slope-intercept form of this line is given by;
![y = mx + c](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6hm7bppno7kne18ecyfnb0sast71uj9zsx.png)
We substitute values to obtain;
![y = - 2x - 2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vgbmlo4b50ba2vx7rbncm335nqxwzibi3n.png)
Since the lower half-plane is shaded the required inequality is
![y \leqslant - 2x - 2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7uszwrxfs0ov8cg8m0qs6zury33elvdwh2.png)