Question

5. If 18 out of 50 lizards sampled has the recessive plan for short tails

a. What would be the proportion of t alleles in the lizard population?
b. What would be the allele frequency for the dominant allele?
C. What percent of the population would be heterozygous?
[Ans -(a)0.6; (b) 0.4; (C) 0.48]

I need to show the work, but I can't figure out how to do any of this, please help!
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Answer 1

The proportion of t alleles in the lizard population is 0.36 or 36%. The allele frequency for the dominant allele is 0.64 or 64%. The percent of the population that would be heterozygous is 0.46 or 46%.

Step-by-step explanation:

To find the proportion of t alleles in the lizard population, we need to determine the frequency of the recessive allele. Since 18 out of 50 lizards have the recessive allele, the proportion of t alleles would be 18/50, which simplifies to 0.36 or 36% (a).

To find the allele frequency for the dominant allele, we can subtract the recessive allele frequency from 1. Since the recessive allele frequency is 0.36 or 36%, the allele frequency for the dominant allele would be 1 - 0.36 = 0.64 or 64% (b).

To find the percent of the population that would be heterozygous, we can calculate 2pq, where p is the dominant allele frequency and q is the recessive allele frequency. Using the allele frequencies from part (a) and (b), the heterozygous proportion would be 2 * 0.64 * 0.36 = 0.46 or 46% (c).

Answer 2

(a) 0.6 because working out the probability

i dont think i actually helped XD