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Help please, anyone thank you

Help please, anyone thank you-example-1

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Answer:

Part A: A (6 , 11) , B (5 , 6) , C (7 , 1) , D (0 , 8)

Part B: A (-6 , -11) , B (-5 , -6) , C (-7 , -1) , D (0 , -8)

Explanation:

* Lets study the reflection about the two axes X and Y

- The distance between the point and the axes of reflection =

the distance between its image and the axes

- The point and the its image are on opposite sides of the axes

- If a point (x , y) reflected about x axis, that means the point

will move vertically

- Moving vertically means we will change the sign of the y-coordinates

∴ The image of (x , y) after reflection about x-axis is (x , -y)

- If a point (x , y) reflected about y axis, that means the point

will move horizontally

- Moving horizontally means we will change the sign of the x-coordinates

∴ The image of (x , y) after reflection about x-axis is (-x , y)

* Now lets use the explanation above to solve our problem

- At first lets right the original point of the quadrilateral ABCD

∵ A (-6 , 11) , B (-5 , 6) , C (-7 , 1) , D (0 , 8)

Part A: The y-axis is the line of reflection

- Lets change the signs of x-coordinates in all points

∴ The new points after reflection about y-axis is:

A (6 , 11) , B (5 , 6) , C (7 , 1) , D (0 , 8)

- Note: The point D does not change because x-coordinate is 0

and there is no sign for the 0

Part B: The x-axis is the line of reflection

- Lets change the signs of y-coordinates in all points

∴ The new points after reflection about x-axis is:

A (-6 , -11) , B (-5 , -6) , C (-7 , -1) , D (0 , -8)

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