Question

A soccer player kicks a ball from the ground with a speed of 16 m/s at an angle of 63°.

A. What is the horizontal component of the velocity?
B. What is the vertical component of the velocity?

Answer 1

A. Horizontal component: 7.3 m/s

Step-by-step explanation:

The horizontal component of the velocity is given by:

`v_x = v_0 cos \theta`

where

`v_0 = 16 m/s` is the magnitude of the initial velocity

`\theta=63^(\circ)` is the angle of the initial velocity with respect to the ground

Substituting numbers into the equation, we find

`v_x = (16 m/s) cos 63^(\circ)=7.3 m/s`

B. Vertical component: 14.3 m/s

Step-by-step explanation:

The vertical component of the velocity is given by:

`v_y = v_0 sin \theta`

where

`v_0 = 16 m/s` is the magnitude of the initial velocity

`\theta=63^(\circ)` is the angle of the initial velocity with respect to the ground

Substituting numbers into the equation, we find

`v_y = (16 m/s) sin 63^(\circ)=14.3 m/s`