Question

A 111.6 g sample of iron was heated from 0°C to 20°C. It absorbed 1004 J of energy. What is the specific heat capacity of iron?

Answer 1

0.45 J/gC

Step-by-step explanation:

The heat absorbed by the sample of iron is given by:

`Q=mC_s (T_f-T_i)`

where:

Q = 1004 J is the heat absorbed

m = 111.6 g is the mass of the sample

Cs is the specific heat capacity of iron

T_f = 20 C is the final temperature of the sample

T_i = 0 C is the initial temperature

Solving the equation for Cs, we find

`C_s = (Q)/(m(T_f-T_i))=(1004 J)/((111.6 g)(20 C-0 C))=0.45 J/gC`