Question

PLs answer fast i need this questions answer

Answer 1

`x=6`

Explanation:

Given equation:

`x-\left(2x-(3x-4)/(7)\right)=(4x-27)/(3)-3`

Expand the left side:

`\implies x-2x+(3x-4)/(7)=(4x-27)/(3)-3`

Let all terms on the left side have the same denominator of 7:

`\implies (7x)/(7)-(14x)/(7)+(3x-4)/(7)=(4x-27)/(3)-3`

Join the terms on the left side:

`\implies (7x-14x+3x-4)/(7)=(4x-27)/(3)-3`

`\implies (-4x-4)/(7)=(4x-27)/(3)-3`

Let all the terms on the right side have the same denominator of 3:

`\implies (-4x-4)/(7)=(4x-27)/(3)-(9)/(3)`

Join the terms on the right side:

`\implies (-4x-4)/(7)=(4x-27-9)/(3)`

`\implies (-4x-4)/(7)=(4x-36)/(3)`

Cross multiply:

`\implies 3(-4x-4)=7(4x-36)`

Expand:

`\implies -12x-12=28x-252`

Add 12x to both sides:

`\implies -12=40x-252`

Add 252 to both sides:

`\implies 240=40x`

Divide both sides by 40:

`\implies 6=x`

`\implies x=6`