Answer:
Explanation:
Okay so solve this this is how you do it
and

To cancel out the X we have to make x into 2 x


we can cancel out -2x and 2x now leaving us with

add them both and solve for y

Now just substitute 2 for y

Or

In both the equations your answer will be the same
Hope this helps :)
If you have an doubt or need further help just reply :)