222k views
1 vote
Find the equation of the line that is parallel to the line x + 5y = 10 and passes through the point (1, 3). A) y = − 1/5 x + 16/5 B) y = −5x − 5/16 C) y = 5x + 10 D) y = 1/5 x − 2

2 Answers

3 votes

Answer:

It's aaaaaaaaaaaaaaaaaaaaaaa!!!

Explanation:

User Joe Ho
by
4.8k points
6 votes

Answer:

A

Explanation:

Parallel lines have the same slope. Find the slope by converting the equation x + 5y = 10 into y = mx+b form. It becomes y = -1/5x + 2. The slope is -1/5.

Substitute -1/5 and the point (1,3) into the point slope form.


y - y_1 = m(x-x_1)\\y - 3 = -(1)/(5)(x - 1)\\y - 3 = -(1)/(5)x + (1)/(5)\\y = -(1)/(5)x + (16)/(5)

User Nomeswaran
by
5.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.