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Find the zero(s) of this function: y=x^2-17x+52

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Answer:

The zeroes are {-4, 13}

Explanation:

Your best bet here is to determine the zeros using the quadratic formula or "completing the square."

Completing the square,

y = x² - 17x +52, or

y = (x - 17/2)² - (17/2)² +52, or

y = (x - 17/2)² - 289/4 +208/4, or

y = (x - 17/2)² - 81/4

We set this = to 0, as we want the zeros. Then:

(x - 17/2)² - 81/4 = 0, or

x - 17/2 = ±9/2, after having taken the square root of both sides.

Thus, one root is x = 17/2 + 9/2, or 26/2, or 13, and the other is

x = 1/2 - 9/2, or -8/2, or -4.

The zeroes are {-4, 13}.

User Natalie Weizenbaum
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User Abdullah Danyal
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