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How do you solve these two problems??​

How do you solve these two problems??​-example-1
User Basit
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1 Answer

7 votes

pythagoras theorem

First one


hypotenuse^2=base^2+perpendicular[tex]10^2=5^2+h^2\\h^2=5^2=10^2\\h^2=25-100\\h^2=75\\h=√(75) \\h=8.7^2[/tex]

c) 8.7m

second one

the surface area of the pyramid


SA=a^(2)+2a\sqrt{(a^2)/(4)+h^2}


12^2+2(12)\sqrt{(12^2)/(4)+11^2} \\144+24√(36+121)\\168√(157)\\444.71

c)528sq ft

User Mannopson
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6.0k points