Part A: 5,333
square yards
EX: The length of the football field is 100 yards. The width of the field is 53
yards.
Part B: 1/10 inch per yard
EX: The scale used in the drawing is 1 inch to 10 yards. I can represent this ratio in several different ways: 1 inch to 10 yards, 1 inch : 10 yards, 1 in/ 10 yd or 1/10
Part C: 10 inches
EX: Set up a proportion where the numerators are the measurements in the scale drawing and the denominators are the actual measurements of the football field:
1 in. / 10 yd. = × in. / 100 yd.
Cross multiply, and then divide both sides by 10 to solve for x:
100 = 10x
10 = x
Part D: 5 1/3
EX: Use the actual width of 53
yards and the scale to find the width of the field in the scale drawing.
Set up a proportion where the numerators are the measurements in the scale drawing and the denominators are the actual measurements of the football field:
1 in / 10 yd = 53
yd
Cross multiply, and then divide both sides by 10 to solve for x:
10x = 53
![(1)/(3)](https://img.qammunity.org/2022/formulas/mathematics/high-school/8c4su5tuu474mta5yxnqkrtvi2n4u8590o.png)
x = 160/3 ÷ 10
x = 16/3
x = 5
![(1)/(3)](https://img.qammunity.org/2022/formulas/mathematics/high-school/8c4su5tuu474mta5yxnqkrtvi2n4u8590o.png)
Part E: 53 1/3
EX: In the scale drawing, the length of the football field is 10 inches and the width is 5
inches. The area of a rectangle is length × width:
area = length × width
= 10 in. x 5
in.
= 53
sq. in. ( square inches)
Part F: The ratio is 1 square inch to 100 square yards
EX: The area of the football field in the scale drawing is 53
square inches.
The area of the actual football field is 5,333
square yards.
The calculation for the ratio of the scaled area to the actual area is
53
sq. in. / 5,333
sq. yd. = 1 sq. in. / 100 sq. yd.
Explanation: