Answer:
![A=0.8836](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cazkk5re92dnhzczgjoqqz9clml15hv4sr.png)
Explanation:
Area of circle:
![\pi r^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/69e2ijkvwardlu2n5rrgtkpqc3b44mcw34.png)
By using the area of a circle, we can get the area of a semicircle:
![(\pi r^2)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5gmeipefla6ag7q0ibub6cgglci1f2kxtw.png)
Let's convert the mixed fraction to an improper fraction and then a decimal:
=
=
![1.5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/18qofyrouspogtgj5t3116l6qyyk010wof.png)
Now, we solved for the diameter, to get the radius, we need to divide the diameter by 2:
![(1.5)/(2) =0.75](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vk9avnagerzms2gvrgva04rizrotfz1jia.png)
Now we have the radius, so we can plug in our values and find the area:
![(\pi0.75^2)/(2) = 0.88357293](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fz9x0crzqe38kf9128dnyya98agf7jgrsj.png)
![A=0.88357293](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9z404xtsaja23j8mhlodflhv0590ayl9kq.png)