Question

What is the distance ?

Answer 1

Pythagoras' Theorem

`c^(2) =\sqrt{a^(2)+b^(2)}`

a = 5

b = 7

`c^(2) =\sqrt{5^(2)+7^(2)}`

`c^(2) =√(25+49)`

`c^(2) =√(74)`

c = 8.6023252627

c = 8.6 to 1d.p.

Answer 2

The distance is 8.6 units

Explanation:

see the image