Answer:
See below
Explanation:
19)
13² = 4² + AM²
169 = 16 + AM ²
AM ² = 153
AM =√153 = √(9× 17) = 3√17
sinA = MT /AT = 4/13
cosA = AM/AT = (3√17)/13
tanA = MT/AM = 4/(3√17) = (4√17)/51
sinT = AM/AT = (3√17)/13
cosT = MT/AT = 4/13
tanT = AM/MT = (3√17)/4
20)
10² = 5² + AJ²
100 = 25 + AJ²
AJ² = 75
AJ = √75 = √(25×3) = 5√3
sinA = JT/AT = 5/10 = ½
cosA = AJ/AT = (5√3)/10 = (√3)/2
tanA = AJ /AJ = 5/(5√3) = (√3)/3
sinT = AJ/AT = (5√3)/10 = (√3)/2
cosT = AJ/AT = 5/10 = ½
tanT = AJ/JT = (5√3)/5 = √3