Question

If c(x) = 4x – 2 and d(x) = x2 + 5x, what is (c0d)(x)

Answer 1

The answer is (cod)(x) = 4x^2 + 20x - 2

Explanation:

In order to find (cod)(x), we need to start with the c(x) equation and then input the d(x) equation for every x in the c(x) equation.

c(x) = 4x - 2

(cod)(x) = 4(x^2 + 5x) - 2

(cod)(x) = 4x^2 + 20x - 2