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which graph contains the points of intersections satisfying this linear-quadratic system of equations? x^2+y^2=20 x-y+2=0

User Charline
by
5.2k points

1 Answer

1 vote

Answer: There are two points of intersection (2, 4) and (-4, -2)

Explanation:

x - y + 2 = 0 → x = y - 2

Use Substitution Method:

x² + y² = 20

(y - 2)² + y² = 20 replaced x with (y - 2)

y² - 4y + 4 + y² = 20 expanded (y - 2)²

2y² - 4y + 4 = 20 added like terms

2y² - 4y - 16 = 0 subtracted 20 from both sides

y² - 2y - 8 = 0 divided both sides by 2

(y - 4)(y + 2) = 0 factored

y - 4 = 0 and y + 2 = 0 applied Zero Product Property

y = 4 and y = -2

Input the y-values into x = y - 2 to solve for x.

y = 4; x = 4 - 2 y = -2; x = -2 - 2

x = 2 x = -4

(2, 4) (-4, -2)

which graph contains the points of intersections satisfying this linear-quadratic-example-1
User KOUSIK MANDAL
by
5.3k points
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