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Find the range of y=4sin2x+3

User Eric Bock
by
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2 Answers

3 votes

Answer:

-1,7

Explanation:

got it right on odessyware

User OverclockedTim
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5.6k points
0 votes

Answer:

[-1, 7]

Explanation:

If you mean ...

y = 4sin(2x) +3

then you can substitute the range of the sine function into the equation and evaluate it to find the range of y.

The range of sin( ) is [-1, 1], so the range of y is ...

4[-1, 1] +3 = [4(-1)+3, 4(1)+3] = [-1, 7]

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Comment on the problem statement

The range of y = 4sin²(x)+3 will be different, and the range of 4sin(2x+3) will be different yet. It is usually a good idea to use parentheses around function arguments.

User Nikolay Makhonin
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5.5k points