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8 votes
8 votes
2sin^2(x)+sin(2x)=2

please help!!

User Hrv
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1 Answer

27 votes
27 votes


2sin {}^(2) (x) + sin(2x) = 2 \\ 2sin {}^(2) (x) + 2sin(x)cos(x) = 2 \\ sin {}^(2) (x) + sin(x)cos(x) - 1 = 0 \\1 - cos {}^(2) (x) + sin(x)cos(x) - 1 = 0 \\ - cos {}^(2) (x) + sin(x)cos(x) = 0


cos(x)( - cos(x) + sin(x)) = 0


cos(x) = 0 \\ x = (\pi)/(2) + k\pi \\ \\ sin(x) = cos(x) \\ x = (\pi)/(4) + k\pi

User Sydridgm
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