Answer:
The measure of the complement angle is
![18\°](https://img.qammunity.org/2020/formulas/mathematics/high-school/ri3k9eeof7dg25y4d7q47y9mpkw7gyop5y.png)
Explanation:
Let
x-----> the angle
we know that
The complement of an angle is equal to
![(90-x)\°](https://img.qammunity.org/2020/formulas/mathematics/high-school/e6fo6qpdjjro028wlu5sty214mh8aej2yp.png)
The supplement of an angle is equal to
![(180-x)\°](https://img.qammunity.org/2020/formulas/mathematics/high-school/5fhm61x8cy2cyo28bu77q6wew4dctfdiwo.png)
we have
The complement of an angle is one-sixth the measure of the supplement of the angle
![(90-x)\°=(1/6)(180-x)\°](https://img.qammunity.org/2020/formulas/mathematics/high-school/aq7p7dsoldejf74zuwzoe1cwkqczetgj9a.png)
solve for x
![(540-6x)\°=(180-x)\°](https://img.qammunity.org/2020/formulas/mathematics/high-school/9ufkx6go2p0taz7g34agebt45roz41qc1h.png)
![(6x-x)=(540-180)\°](https://img.qammunity.org/2020/formulas/mathematics/high-school/9vj1g9ylya2l85hjoeijcbw3xie31s9cww.png)
![(5x)=(360)\°](https://img.qammunity.org/2020/formulas/mathematics/high-school/aenbxtzvxgrwsu9127lkxbwvel2auwyxpx.png)
![x=72\°](https://img.qammunity.org/2020/formulas/mathematics/high-school/eib7vuxagorl639aad99cphiifwcoq8nbs.png)
Find the measure of the complement angle
------>
![(90-72)=18\°](https://img.qammunity.org/2020/formulas/mathematics/high-school/5mw3gw98bgzh0bjpnjgnnu0xbwr4fukjmg.png)