Question

Pls help picture provided

Answer 1

`33`

Explanation:

The given quadratic equation is

`1=2x^2+5x`

We want to rewrite this equation in the form;

`ax^2+bx+c=0`

We add
`-1` to both sides of the equation to obtain;

`0=2x^2+5x-1`

This is the same as

`2x^2+5x-1=0`

This implies that;

`a=2,b=5,c=-1`

We substitute these values into the expression
`b^2-4ac`

`\Rightarrow 5^(2)-4(2)(-1)`

`=25+8`

`=33`

Answer 2

Answer: second option

Explanation:

The standard form of a quadratic equation is:

`ax^2+bx+c=0`

Then, to write the quadratic equation given in the problem in standard form, you must substract 1 from both sides of the equation. Then you have:

`2x^2+5x-1=0`

Given the quadratic equation above, to find the value of
`b^2-4ac` you must substitute:

a=2; b=5 and c=-1 into
`b^2-4ac`

Thenrefore, you obtain the following result:

`5^2-4(2)(-1)=33`