Question

Identify the brønsted-lowry acid, the brønsted-lowry base, the conjugate acid, and the conjugate base in each reaction: (a) c5h5n(aq)+h2o(l)⇌c5h5nh+(aq)+oh−(aq) (b) hno3(aq)+h2o(l)⇌h3o+(aq)+no3−(aq) drag the appropriate items to their respective bins.

Answer 1

acids give away protons (H+), bases accept protons, conjugate bases are what u get when when you take the protons from the acid, and conjugate acids are what u get when you add the protons to the base.

so for (a) the C5H5N is the base, water is the acid, C5H5NH+ is the conj acid, OH- is the conj base

(b) HNO3 is the acid, H2O is the base, hydronium ion is the conj. acid, NO3- is the conj base.

Answer 2

Answer: a)
`C_5H_5N(aq.)+H_2O(l)\rightarrow C_5H_5NH^+(aq.)+OH(aq.)`

bronsted- lowry acid :
`H_2O`

conjugate base :
`OH^-`

bronsted- lowry base :
`C_5H_5N`

conjugate acid :
`C_5H_5NH^+`

b)
`HNO_3(aq)+H_2O(l)\rightarrow H_3O^+(aq.)+NO_3^-(aq.)`

bronsted-lowry acid :
`HNO_3`

conjugate base :
`NO_3^-`

bronsted- lowry base :
`H_2O`

conjugate acid :
`H_3O^+`

Step-by-step explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

For the given chemical equation:

a)
`C_5H_5N(aq.)+H_2O(l)\rightarrow C_5H_5NH^+(aq.)+OH(aq.)`

Here,
`H_2O` is loosing a proton, thus it is considered as a brønsted-lowry acid and after losing a proton, it forms
`OH^-` which is a conjugate base.

And,
`C_5H_5N` is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms
`C_5H_5NH^+` which is a conjugate acid.

b)
`HNO_3(aq)+H_2O(l)\rightarrow H_3O^+(aq.)+NO_3^-(aq.)`

Here,
`HNO_3` is loosing a proton, thus it is considered as a brønsted-lowry acid and after losing a proton, it forms
`NO_3^-` which is a conjugate base.

And,
`H_2O` is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms
`H_3O^+` which is a conjugate acid.