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Solve the triangle. Round lengths to the nearest tenth and angle measures to the nearest degree. B = 15° C = 113° b = 49

A = 50°, a = 174.3, c = 149.2

A = 52°, a = 151.2, c = 176.3

A = 52°, a = 149.2, c = 174.3

A = 50°, a = 176.3, c = 151.2

2 Answers

6 votes

Answer:

A = 52°, a = 149.2, c = 174.3

Explanation:

Technology is useful for this. Many graphing calculators can solve triangles for you. The attachment shows a phone app that does this, too.

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The Law of Sines can give you the value of c, so you can choose the correct answer from those offered.

c = sin(C)·b/sin(B) = sin(113°)·49/sin(15°) ≈ 174.271 ≈ 174.3 . . . . . third choice

Solve the triangle. Round lengths to the nearest tenth and angle measures to the nearest-example-1
User Nodeffect
by
6.1k points
4 votes

Answer:

A = 52°, a = 149.2, c = 174.3

Explanation:

We are given the following two known angles and one known side length for a triangle and we are to find the rest of the side lengths and angle:

B = 15° C = 113° b = 49

A = 180 - ( 15 + 113) = 52°

For finding the side lengths, we can use the sine rule:


(a)/(sin(A))=(b)/(sin(B))


(a)/(sin(52)) =(49)/(sin(15))

a = 149.2


(c)/(sin(C))=(b)/(sin(B))


(c)/(sin(113)) =(49)/(sin(15))

c = 174.3

User Pratteek Shaurya
by
5.6k points