Answer: Option A
(A) first Graph (1,6)
Explanation:
f(x)= 2(3)^x
putting x = 0
y = f(0) = 2(3)^0= 2
so at x = 0 y should be 2
putting x = 1
y = 2(3)^1 = 6
so at x = 1 y should be 6
select the graph which has these points
so option A is your answer
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