227k views
0 votes
Which statement proves that Quadrilateral HIJK is a kite???

Which statement proves that Quadrilateral HIJK is a kite???-example-1

2 Answers

3 votes

Answer:

B. IH = IJ = 3 and JK = HK = StartRoot 29 EndRoot, and IH ≠ JK and IJ ≠ HK.

Explanation:

User John Driscoll
by
5.3k points
4 votes

Answer:

Option B. is the answer.

Explanation:

In the given picture we have to prove that quadrilateral HIJK is a kite.

1. For a kite quadrilateral HIJK will be a kite, if it's sides IJ = IH

From the graph length of I H = 4 - 1 = 3 units

Length of IJ = 0 - (-3) = 3 units

Therefore, IJ = IH = 3 units

2. Sides HK should be equal to JK

Length of HK =
\sqrt{[1-(-1)]^(2)+[2-(-3)^(2) by Pythagoras Theorem

=
\sqrt{(2)^(2)+(5)^(2)}=√(4+25)=√(29)

Similarly length of JK =
\sqrt{(2)^(2)+[4-(-1)]^(2)}=\sqrt{4+5^(2) }

=
√(29)

Therefore HK = JK = √29 units

3). IH ≠ JK and ij ≠ HK

All these conditions are fulfilled for HIJK to be a kite.

Option B. is the answer.

User Jurian Sluiman
by
5.4k points