Answer:
Explanation:
Given that before 1918, approximately 55% of the wolves in the New Mexico and Arizona region were male, and 45% were female.
a) Before 1918, in a random sample of 9 wolves spotted in the region, we have to find that the probability 6 or more were female
Let X be the no of males in the sample of 9 wolves
Each wolf is independent of the other to be male
Also there are only two outcomes
We have p = success for each outcome = 0.70
q =1-p =0.30
X is binomial with (9, 0.70)
the probability that 6 or more were male
=
![P(x\geq 6) \\=P(6)+P(7)+P(8)+P(9)+P(10)\\](https://img.qammunity.org/2020/formulas/mathematics/high-school/ukxkterw6n49x54txhfp88lm3rvw8qxduj.png)
=
![\Sigma_6^9 9Cr (0.7)^r (0.3)^(9-r)](https://img.qammunity.org/2020/formulas/mathematics/high-school/2x5cay83ar6nif1a0kqh7lb8y7xsqzv9ox.png)
=0.7297