How many moles of methanol (CH3OH) are contained in 82.5 g methanol?

asked May 1, 2020 17.8k views

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6 votes

Methanol's molar mass is 32 g/mol. So there are

$82.5 / 32 = 2.578125 \: mol$

The general formula is:

$number \: of \: moles = (mass \: in \: grams)/(molar \: mass)$

Vinessa answered May 8, 2020

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