Answer:
Part a) The equation that determine the original price per pound is equal to
![3(p+0.75)=5.88](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t3useccteycsemvq1inyxknib3a9u655m1.png)
Part b) The original price per pound is
![\$1.21](https://img.qammunity.org/2020/formulas/mathematics/middle-school/z7osznykb5l1gac6u6du1x9t1yl4lknace.png)
Explanation:
Let
p-----> the original price per pound
x-----> the new price per pound
we know that
-----> equation A
----> equation B
substitute equation A in equation B
-----> equation that determine the original price per pound
solve for p
![3p+2.25=5.88](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ocaeode7atoewob6yxmdtf1dpx7jhl2c99.png)
![3p=5.88-2.25](https://img.qammunity.org/2020/formulas/mathematics/middle-school/glyv82ivy8agvuncxn6upokooysecb5353.png)
![3p=3.63](https://img.qammunity.org/2020/formulas/mathematics/middle-school/so80pccnci5npb3vw5gr6wewprum73l0mh.png)
![p=3.63/3=\$1.21](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8zzlnyjd1oancgmw37k72cqw1ke2o6mffp.png)