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To what temperature must 32.0ft^3 of a gas at 2°C be heated for it to occupy 1.00 x 10^2ft^3 at the same time?

User Nebulosar
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2 Answers

4 votes

Answer:

859 k or 586 °C

Step-by-step explanation:

User Cooshal
by
4.4k points
4 votes

Answer;

859 k or 586 °C

Explanation;

According to Charles's law, the volume of a fixed mass is directly proportional to absolute temperature at constant pressure.

Therefore;

V1/T1 = V2/T2

V1 = 32 ft³, T1 = 273 + 2 = 275 K

V2 = 100 ft³, T2 = ?

Thus;

32 ft³/275 K = 100 ft³/T2

Hence;

T2 = 859 k or 586 °C

User Datcn
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4.3k points