2 Answers

Jeffrey Chung · Answer 1 · 2020-05-13T19:48:14+0000

Answer:

The approximate volume of the remaining solid is
$140.64\ in^(3)$

Explanation:

we know that

The approximate volume is equal to the volume of the cube minus the volume of the cylinder

so

$V=b^(3)-\pi r^(2)h$

we have

$b=6\ in$

$r=4/2=2\ in$ -----> the radius is half the diameter

$h=6\ in$

substitute the values

$V=6^(3)-(3.14)(2^(2))(6)=140.64\ in^(3)$

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