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Express each logarithm in terms of In 2 and In 5.


In(32)/(125)


In12.5

User Blacklabel
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1 Answer

6 votes

Answer:


5ln2-3ln5


2ln5-ln2

Explanation:


32=2^(5)


125=5^(3)


ln(32)/(125)=ln(2^(5))/(5^(3))


ln2^(5)-ln5^(3)=5ln2-3ln5


12.5=(125)/(10)=(25)/(2)=(5^(2))/(2)


ln12.5=ln(5^(2))/(2)


ln5^(2)-ln2=2ln5-ln2

User Powisss
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