Answer:
10.08 L.
Step-by-step explanation:
- If we assume that CO₂ gas behaves ideally at STP (standard T(0.0 °C) and P(1.0 atm)):
It is known that 1.0 mole of ideal gas occupies 22.4 L at STP conditions.
Using cross multiplication:
1.0 mole of CO₂ gas occupies → 22.4 L.
0.45 mole of CO₂ gas occupies → ??? L.
∴ The volume occupied by 0.45 mole of CO₂ gas = (0.45 mol)(22.4 L)/(1.0 mol) = 10.08 L.