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PLEASE PLEASE HELP ASAP

A cyclist speeds up from 3 m/s to 7 m/s in 8 seconds.

What is its change in velocity?

What's its acceleration?

User Rplantiko
by
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1 Answer

6 votes

Answer:

Change in velocity = 4 m/s and acceleration = 0.5 m/s²

Step-by-step explanation:

Given that,

Initial velocity, u = 3 m/s

Final velocity, v = 7 m/s

Time, t = 8 seconds

(a) The change in velocity of a cyclist.


\Delta v=v-u\\\\=7\ m/s-3\ m/s\\\\=4\ m/s

(b) Acceleration,


a=(\Delta v)/(t)\\\\a=(4\ m/s)/(8\ s)\\\\a=0.5\ m/s^2

So, the change in velocity is 4 m/s and acceleration is 0.5 m/s².

User Mzy
by
5.1k points