Answer:
![2.43\cdot 10^5 J](https://img.qammunity.org/2020/formulas/physics/high-school/1az9wpiziczk927aab1j3fy9mi9jaj5dmc.png)
Step-by-step explanation:
Since the force applied is parallel to the displacement of the car, the work done on the car is simply given by:
![W=Fd](https://img.qammunity.org/2020/formulas/physics/high-school/d8vjw5oltzw7zvw8lsm9mtjiskvxowyao9.png)
where
F = 1210 N is the force applied on the car
d = 201 m is the displacement of the car
Substituting numbers into the equation, we find:
![W=(1210 N)(201 m)=2.43\cdot 10^5 J](https://img.qammunity.org/2020/formulas/physics/high-school/hjuebbauoci289zjhkdg6ze6yeb2lvex8f.png)