Question

5-A baseball is hit with a velocity of 15 m/s at an angle of 40° in the horizontal direction. What are the horizontal and vertical vector components of the velocity vector?

A•Horizontal =9.64 m/s
Vertical=11.49 m/s

B•Horizontal=11.49 m/s
Vertical=9.64 m/s

C•Horizontal=25 m/s
Vertical=25 m/s

D•Horizontal =75 m/s
Vertical =75 m/s

Number 6 is in the picture. TIA

Answer 1

B•Horizontal=11.49 m/s

Vertical=9.64 m/s

Using the concept of a trigonometric ratios,

sin θ = y/hypotenuse

where y is the vertical component.

sin 40 = y/15

y = 15 × sin 40

= 9.64 m/s

vertical component = 9.64 m/s

cos θ = x/hypotenuse

where x is the horizontal component

cos 40 = x/15

x = 15 × cos 15

=11.49

Horizontal component = 11.49 m/s