Question

What is the equation of a line that passes through the points (–3, 4) and (2, 8)?

Answer 1

=5

Explanation:

4-9= -5

2-3 = -1

=5

.....

Answer 2

y = \frac{4}{5}x + \frac{32}{5}

Explanation:

(x₁ , y₁) = (-3, 4) & (x₂ , y₂) = (2 , 8)

Slope =
`(y_(2)-y_(1))/(x_(2)-x_(1))\\`

`= (8-4)/(2-[-3])\\\\= (8-4)/(2+3)\\\\= (4)/(5)`

m = 4/5 ;

Equation of the line: y - y₁ = m(x - x₁)

`y - 4 = (4)/(5)(x - [-3])\\\\y - 4 = (4)/(5)(x +3)\\\\y - 4 = (4)/(5)x + (4)/(5)*3\\\\ y = (4)/(5)x + (12)/(5)+4\\\\ y = (4)/(5)x + (12)/(5) + (4*5)/(1*5)\\\\ y =(4)/(5)x + (12)/(5) +(20)/(5)\\\\ y = (4)/(5)x + (32)/(5)`