Question

At 650 mm hg a gas has a volume of 190 l what is its volume at standard pressure

Answer 1

Answer:Volume occupied by the gas at standard pressure is 162.5 L.

Step-by-step explanation:

Pressure of the gas when it occupies volume of 190 L = 650 mmHg

Volume occupied by the gas when the gas is at standard pressure.

The value of standard pressure = 1 atm = 760 mmHg

`P_1=650 mmHg,V_1=190 L,P_2=760 mmHg,V_2=?`

According to Boyle's Law:
`Pressure\propto (1)/(Volume)` (at constant temperature)

`P_1* V_1=P_2* V_2`

`V_2=(P_1* V_1)/(P_2)=(650 mmHg* 190 L)/(760 mmHg)=162.5 L`

Volume occupied by the gas at standard pressure is 162.5 L.