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A point with an abscissa of 3 belongs to the line which is the graph of the equation 21x–5y=100. Find the ordinate of that point.

User Jarekczek
by
5.1k points

2 Answers

5 votes

The ordinate will be -7.4.

User Mohammad Hizzani
by
5.3k points
7 votes

Answer:

-7.4

Explanation:

Put the abscissa value into the equation and solve for the ordinate.

21·3 -5y = 100

-5y = 37 . . . . . subtract 63

y = -7.4 . . . . . . divide by -5

User Nick Van Brunt
by
5.5k points
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