Answer:
c. Jupiter's radius is 10 times the Earth's radius
Step-by-step explanation:
The weight of a person on the surface of a planet is equal to the gravitational pull exerted by the planet on the person:
![F=G(mM)/(R^2)](https://img.qammunity.org/2020/formulas/physics/high-school/9no52i5gp9kxhccuy5ombecqv7vu65qwzn.png)
where
is the gravitational constant
M is the mass of the planet
m is the mass of the person
R is the radius of the planet
The weight of a person on Earth is given by:
![F_E=G(mM_E)/(R_E^2)](https://img.qammunity.org/2020/formulas/physics/high-school/ost8bu1nhei2u23itzkvvqsnfeg0wezhuo.png)
where
is the mass of the Earth and
is the Earth's radius.
We know that Jupiter's mass is 300 times the Earth's mass:
![M_J = 300 M_E](https://img.qammunity.org/2020/formulas/physics/high-school/7cweq6u49w2g4mqn1plomqrjvjx0zvox91.png)
while Jupiter's radius is 10 times the Earth's radius:
![R_J = 10 R_E](https://img.qammunity.org/2020/formulas/physics/high-school/rdcgt83wbnvv6ap7aec6vi2lz16t43uuqk.png)
So, the weight of the person on Jupiter is
![F_J=G(mM_J)/(R_J^2)=G(m(300 M_E))/((10 R_E)^2)=G (300 mM_E)/(100 R_E^2)=3 G(mM_E)/(R_E^2)=3 F_E](https://img.qammunity.org/2020/formulas/physics/high-school/rw1yi8n6cu0n0uqnhiq20o49uhfdioz9fw.png)
So, the weight would be only 3 times as much.