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Determine the molarity for the fixer Sodium carbonate decahydrate (I dissolved 127.62 grams of sodium carbonate for every 4 liters of water)

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Answer:

0.112 M.

Step-by-step explanation:

  • Molarity is the no. of moles of solute in a 1.0 L of the solution.

M = n/V.

M = (mass/molar mass)solute x (1000/V of the solution).

mass = 127.62 g.

molar mass = 286.138 g/mol.

V of the solution = 4.0 L = 4000.0 mL.

∴ M = (mass/molar mass)solute x (1000/V of the solution) = (127.62 g / 286.138 g/mol) x (1000 / 4000.0 mL) = 0.1115 M ≅ 0.112 M.

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