Answer:
The measure of angle A is 53.13°.
Explanation:
Given,
ABC is a triangle,
In which m∠CBA = 90°, AB = 3 cm, BC = 4 cm and CA = 5 cm,
By the law of sine,
![(sinA)/(BC)=(sinB)/(AC)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nn4s4j8elujyou8uifvxm7ssxbjxh1ix10.png)
( By cross multiplication )
By substituting the values,
![sin A = 4* (sin 90^(\circ))/(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/64nmtraepkav5vy01913hctwnkv26mbwrk.png)
( sin 90° = 1 )
![\implies m\angle A =53.1301023542^(\circ)\approx 53.13^(\circ)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/72yn0qet4mur6t0ujqhfwvwg2yvgosq1gr.png)
Hence, the measure of angle A is 53.13°.