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What would be the pH of a solution whose [OH-] is 2.8 × 10-5M?
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What would be the pH of a solution whose [OH-] is 2.8 × 10-5M?

User NateQ
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1 Answer

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pOH= - log [OH-]

pOH=-log[2.8E-5]

pOH= 4.55

pOH + pH= 14

pH= 14 - 4.55

pH= 9.45

SORRY IF THIS IS WRONG

User Daywon
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