Answer:
90 suits per week must be produced and sold to achieve the maximum profit of $2,850.
Step-by-step explanation:
The profit function is given by the revenue function minus the cost function:
![P(x) = R(x) - C(x)\\P(x)=120x -1200-30x-0.5x^2](https://img.qammunity.org/2020/formulas/business/high-school/7so8ufad5hcodqh1aajssutj12cqo0gsfq.png)
The number of suits, x, for which the derivate of the profit funtion is zero, is the production volume that maximizes profit:
![P'(x)=0=120-30-x\\x=90\ suits](https://img.qammunity.org/2020/formulas/business/high-school/29x85sshx1is14812emftapro334aajmwo.png)
The profit generated by producing 90 suits is:
![P(90)=120*90 -1200-30*90-0.5*90^2\\P(90) = \$2,850](https://img.qammunity.org/2020/formulas/business/high-school/3yu5s7hwbmv8ed2174r0d1r3my1xgmyq1j.png)
Therefore, 90 suits per week must be produced and sold to achieve the maximum profit of $2,850.