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How many grams of CO are produced when 35.2g of C reacts

User Sethu
by
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2 Answers

7 votes

6.5 g Fe2O3 x 1 mol Fe2O3/ 159.9 g Fe2O3 x 2 mol Fe/1 mol Fe2O3 x 55.8 g Fe/ 1 mol Fe = 4.5 g Fe <<< Answer

Steps:

1) start with reactant provided in the question.

2) calculate the grams per mole of that reactant.

3) determine the ratio of the given reactant to the (desired) reactant in the question.

4) calculate the grams per mole of the desired reactant.

If everything cancels out, you've set your factors up properly

User CigarDoug
by
8.6k points
3 votes

Answer:


m_(CO)=82.13gCO

Step-by-step explanation:

Hello,

Considering the reaction:


2C+O_2\rightarrow 2CO

By means of stoichiometry, the produced grams of CO result:


m_(CO)=35.2gC*(1molC)/(12gC)*(2molCO)/(2molC)*(28gCO)/(1molCO) \\m_(CO)=82.13gCO

Best regards.

User Frank Kusters
by
7.9k points

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