Answer:
Second option x
Explanation:
We have the function
![y = √(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yu61j7oj9dtmcrlky8z0r38hzq7lmb4y1h.png)
We know that the square root of a negative number has no solution in the real ones. Therefore the domain of this function is
![x > 0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9e24wex7o7k2898nfmc2tujjfsfktn9yma.png)
When applying the transformation:
we have a translation of the original function in 7 units to the right and 2 units to the top:
![f(x) = √(x-7) + 2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/j1s48tn8o19wxud3lo5d09obhk1b1do52z.png)
In the same way we must guarantee that
![(x-7)> 0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2dedmgz15xq7tw9d2eknqoq5ypf94bj1p7.png)
Then
.
Therefore the domain of f(x) is x