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Please help

number 4 and 6​

Please help number 4 and 6​-example-1
User Vame
by
5.3k points

1 Answer

4 votes

Answer:

4a. See attached.

4b. 32

6. x = 4.5, LM = 7.5, LN = 10.5

Explanation:

4b. The midline of a triangle is half the length of the baseline it is parallel to. Hence the segment FH is twice the length of CD, or 2·16 = 32.

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6. The angle bisector MP divides the triangles segments so those on one side of it are proportional to corresponding ones on the other side of it. Here, that means ...

x/(x+3) = 6/10

10x = 6x + 18 . . . . multiply by 10(x+3)

4x = 18 . . . . . . . . . subtract 6x

x = 4.5 . . . . . . . . . divide by 4

Then segment LM is x+3 = 4.5+3 = 7.5, and LN = x+6 = 4.5+6 = 10.5.

The blanks are filled as ...

x = 4.5 LM = 7.5 LN = 10.5

Please help number 4 and 6​-example-1
User Smiles
by
5.4k points
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