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3x^2+5x+2 factor the expression

User Darkpool
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1 Answer

1 vote

Answer:

Explanation:

One factor must end in 2 and the other in 1, so as to get the constant term +2 of the given expression. Possible roots are plus or minus 1, 2, 1/3 (for starts).

Use synthetic division to determine whether a possible root actually is a root. If we choose to check out 1/3 as a possible root, we'd use:

1/3 / 3 5 2

1 2

----------------------

3 6 4 Since the remainder is not zero, 1/3 is not a root.

Apply the quadratic formula. Here a = 3, b = 5 and c = 2, so the discriminant is b^2 - 4ac, or 25 - 4(3)(2) = 25 - 24 = 1, and the roots are

-5 ± √1

x = ------------- = -6/6 (or -1) and -4/6 = -2/3

6

Back to synthetic division:

-2/3 / 3 5 2

-2 -2

-------------------

3 3 0 (Remainder is zero).

Since -2/3 is a root, (3x + 2) is a factor. The coefficients of the quotient

(found immediately above) are 3 3, indicating a factor of 3(x + 1).

User Dushyant Dagar
by
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